What Is The Volumme Of Container That Can Hold 0.75 Mole Of Gas At 30.0degreecelsius And 100.0 Kpppa

WHAT IS THE VOLUMME OF CONTAINER THAT CAN HOLD 0.75 MOLE OF GAS AT 30.0DEGREECELSIUS AND 100.0 KPPPA

 

Good Day..

problem:

WHAT IS THE VOLUMME OF CONTAINER THAT CAN HOLD 0.75 MOLE OF GAS AT 30.0°C AND 100.0 kPA.

Note:

Convert degree celsius to kelvin when solving gas laws problem.

kelvin = degree celsius + 273.15

kelvin = 30 + 273.15 = 303.15 K

Given Data:

n (amount in moles) = 0.75 mol

T (temperature kelvin) = 30.0°C (303.15 K)

P (pressure)   = 100 kPa

V (volume)    = ? unknown

R (for Kpa unit of pressure) = 8.31 kPa . L / mol.K

Solution:

We can used the formula for ideal gas law which is PV=nRT

To solve for Volume we can use V = nRT / P

V = nRT / P

   = 0.75 mol × 8.31 kPa.L/mol.K × 303.15 K  /   100 kPa

   = 1889.382 L / 100

  = 18.894 L

Answer:

Volume is 18.894 L

Hope it helps...=)


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