"If A Sample Of Gas Occupies 6.8l At 327c,What Will Its Volume Be At 27c If The Pressure Does Not Change?"

If a sample of gas occupies 6.8L at 327C,what will its volume be at 27C if the pressure does not change?

 

Good Day...

Problem:

If a sample of gas occupies 6.8L at 327C,what will its volume be at 27C if the pressure does not change?

Note: in solving any gas law problems, kelvin temperature will be used.

kelvin = degree celsius + 273.15

  • Kelvin = 327 + 273.15

                   = 600.15 K

  • Kelvin = 27 + 273.15

                   =  300.15 K

Given Data;

V1 (initial volume) = 6.8 L                V2 (final volume) = ? unknown

T1 (initial temperature = 327 C      T2 (final temperature) = 27 C

                           ( 600.15 K)                                       (300.15 K)

Solution:

  • This problem can be solve using Charles Law which states that volume is directly proportional to kelvin temperature of gases if amount of gas and pressure are constant. If temperature decreases, volume decreases.
  • Formula of Charles Law is V1/T1 = V2/T2
  • To solve for V2, we can used the formula V2 = V1T2 / T1

V2 = V1T2 / T1

     = 6.8 L × 300.15 K / 600.15 K       (cancel the unit kelvin)

     = 2041.02 L / 600.15

V2 = 3.401 L

Answer:

volume is 3.401 L

Hope it helps...=)

                         


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